Ruthenium–tin complexes from the reaction of HSnPh3 with Ru3(CO)10(NCMe)2 and their reactions with bis(tri-t-butylphosphine)platinum

The compounds Ru3(CO)9(SnPh3)2(NCMe)(μ-H)2 (1), Ru3(CO)10(SnPh3)2(μ-H)2 (2), Ru(CO)4(SnPh3)2 (3) and Ru(CO)4(SnPh3)(H) (4) were obtained from the reaction of Ru3(CO)10(NCMe)2 with HSnPh3 in hexane solvent. Compounds 1, 3 and the new compound Ru3(CO)7(SnPh3)3(NCMe)2(μ-H)3 (5) were obtained from reaction of Ru3(CO)10(NCMe)2 with HSnPh3 in a CH2Cl2 and MeCN solvent mixture. Compound 2 and the new compound Ru3(CO)9(SnPh3)3(μ-H)3 (6) were obtained from reactions of 1 and 5 with CO, respectively. Compounds 2 and 6 eliminated benzene when heated to yield Ru3(CO)10(μ-SnPh2)2 (7) and Ru3(CO)9(μ-SnPh2)3 (8) which contain bridging SnPh2 ligands. Compound 7 was found to react with View the MathML sourcePt(PBu3t)2 to yield the View the MathML sourcebis-Pt(PBu3t) adduct, View the MathML sourcePt2Ru3(CO)10(PBu3t)2(μ3-SnPh2)2 (9) in 59% yield by the addition of View the MathML sourcePt(PBu3t) groups to two of the Ru–Sn bonds to the bridging SnPh2 ligands. Fenske–Hall molecular orbital calculations were performed to provide an understanding of the metal–metal bonding in the clusters of 7 and 9. Compounds 1, 2, 5, 6, 7 and 9 were characterized structurally by single crystal X-ray diffraction analysis.