doubly even code
exists. In [3] the odd prime numbers which can divide the order of the group of
were determined and
is the largest of these. Twenty-three is eliminated by reducing the problem to the consideration of
codes, each of which is shown to have minimum weight
or less. One of these codes, denoted by
, arises from the
construction where
and
are in one quadratic residue code and
is in the other. The weight distribution of
is given.